Y=x^2+21x+540

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Solution for Y=x^2+21x+540 equation: 



=Y^2+21Y+540

We move all terms to the left:

-(Y^2+21Y+540)=0

We get rid of parentheses

-Y^2-21Y-540=0

We add all the numbers together, and all the variables

-1Y^2-21Y-540=0

a = -1; b = -21; c = -540;
Δ = b2-4ac
Δ = -212-4·(-1)·(-540)
Δ = -1719
Delta is less than zero, so there is no solution for the equation

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